package com.lishem.carl._04string;

/**
 * https://leetcode.cn/problems/reverse-string/description/
 * <p>
 * 编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 s 的形式给出。
 * <p>
 * 不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
 * <p>
 * 示例 1：
 * <p>
 * 输入：s = ["h","e","l","l","o"]
 * <p>
 * 输出：["o","l","l","e","h"]
 * <p>
 * 示例 2：
 * <p>
 * 输入：s = ["H","a","n","n","a","h"]
 * <p>
 * 输出：["h","a","n","n","a","H"]
 */
public class _1LetCode344_反转字符串 {

    public void reverseString(char[] s) {
        int left = 0;
        int right = s.length - 1;
        while (left < right) {
            char c = s[left];
            s[left++] = s[right];
            s[right--] = c;
        }
    }

    public static void main(String[] args) {
        _1LetCode344_反转字符串 sol = new _1LetCode344_反转字符串();
        char[] char1 = "hello".toCharArray();
        sol.reverseString(char1);
        System.out.println(new String(char1));

        char[] char2 = "Hannanh".toCharArray();
        sol.reverseString(char2);
        System.out.println(new String(char2));
    }
}
